11a^2-2=0

Solution for 11a^2-2=0 equation:

11a^2-2=0

a = 11; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·11·(-2)
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{22}}{2*11}=\frac{0-2\sqrt{22}}{22}
=-\frac{2\sqrt{22}}{22}
=-\frac{\sqrt{22}}{11}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{22}}{2*11}=\frac{0+2\sqrt{22}}{22}
=\frac{2\sqrt{22}}{22}
=\frac{\sqrt{22}}{11}
$